Heat lost = heat gained
20kg * 4200Kg-1K-1 * (80-40) K = x * 4200JKg-1K-1 * (40-15) K
X = 3, 360, 000/25, 000 = 32kg.
3. 0.2kg of iron at 200C is dropped into 0.09kg of water at 260C inside a calorimeter of mass 0.15kg and s.h.c.
800JKg-1K-1. Find the final temperature of the water. Take the s.h.c. of iron = 460JKg-1K-1 and that of water
= 4200JKg-1K-1
Moraa orina answered the question on April 10, 2018 at 17:53
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